Let $A = [a_{i j}] = ⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 4 & 8 6 & 2 & 5 3 & 7 & 0 9 & - 2 & - 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦$ . Find
(i) the order of the matrix
(ii) the elements $a_{13}$ and $a_{42}$
(iii) the position of the element 2.

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Solution

$A = [a_{i j}] = ⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 4 & 8 6 & 2 & 5 3 & 7 & 0 9 & - 2 & - 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦$
$i) .$ Order of the matrix is $4 \times 3.$
$i i) . a_{13} = 8,$ $a_{42} = - 2$
$i i i) .$ Position of element $2$ is $a_{22} .$
Hence, solved.

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Similar questions

In the matrix, write :
$A = ⎡ ⎢ ⎢ ⎣ \begin{matrix} 235 \sqrt{3} \end{matrix} \begin{matrix} 5 - 2 1 \end{matrix} \begin{matrix} 19 \frac{5}{2} - 5 \end{matrix} \begin{matrix} - 7 1217 \end{matrix} ⎤ ⎥ ⎥ ⎦$

(i) The order of the matrix
(ii) The number of elements
(iii) Write the elements $a_{13}, a_{21}, a_{33}, a_{24}, a_{23}$

In the matrix $⎡ ⎢ ⎢ ⎣ \begin{matrix} 2 & 5 & 19 & - 7 35 & - 2 & \frac{5}{2} & 12, \sqrt{3} & 1 & - 5 & 17 \end{matrix} ⎤ ⎥ ⎥ ⎦$ ,write
(i)the order of the matrix

(ii)The number of elements,

(ii)The elements $a_{13}, a_{21}, a_{33}, a_{24}, a_{23} .$

In the matrix, write:

(i) The order of the matrix (ii) The number of elements,

(iii) Write the elements a₁₃, a₂₁, a₃₃, a₂₄, a₂₃

Construct $2 \times 2$ matrix, $A = [a_{i j}]$ whose elements are given by
$(i i i) a_{i j} = \frac{(i + 2 j)^{2}}{2}$

Q. Write the element

a_{12}

of the matrix

A = {[a_{i j}]}_{2 \times 2}

, whose elements

a_{i j}

are given by

a_{i j} = e^{2 i x} sin j x

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Let A=[aij]=⎡⎢ ⎢ ⎢⎣1486253709−2−1⎤⎥ ⎥ ⎥⎦. Find(i) the order of the matrix(ii) the elements a13 and a42 (iii) the position of the element 2.

A=[aij]=⎡⎢ ⎢ ⎢⎣1486253709−2−1⎤⎥ ⎥ ⎥⎦i). Order of the matrix is 4×3.ii).a13=8, a42=−2iii). Position of element 2 is a22.Hence, solved.

Let $A = [a_{i j}] = ⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 4 & 8 6 & 2 & 5 3 & 7 & 0 9 & - 2 & - 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦$ . Find
(i) the order of the matrix
(ii) the elements $a_{13}$ and $a_{42}$
(iii) the position of the element 2.

$A = [a_{i j}] = ⎡ ⎢ ⎢ ⎢ ⎣ \begin{matrix} 1 & 4 & 8 6 & 2 & 5 3 & 7 & 0 9 & - 2 & - 1 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎦$
$i) .$ Order of the matrix is $4 \times 3.$
$i i) . a_{13} = 8,$ $a_{42} = - 2$
$i i i) .$ Position of element $2$ is $a_{22} .$
Hence, solved.