Let A and B be two sets such that n(A)=6 and n(B)=3. If x denotes the number of onto functions from A to B and y denotes the number of one-one functions from B to A, then the value of x−y is equal to
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Solution
Given n(A)=6,n(B)=3
x= Number of onto functions from A to B =3C0⋅36−3C1⋅26+3C2⋅16=540 y= Number of one-one functions from B to A =6P3=120 ∴x−y=420