Let A and B be two square matrices of order 3 such that A-5 and B-2- Then the value of B- A is

Given : (A)=5 and (B)=2 We know that (K· A)=K^n(A), where n is the order of nbsp;determinant and K∈ℝ nbsp; Now, ((B)· A)=(2· A ) =2^3·(A) =8(A) ∴((B)· A)=40 ...

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Byju's Answer

Standard IX

Mathematics

Scalar Matrix

Let A and B b...

Question

Let $A$ and $B$ be two square matrices of order $3$ such that $det (A) = 5$ and $det (B) = 2.$ Then the value of $det (det (B) \cdot A)$ is

40

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Solution

The correct option is A $40$
Given : $det (A) = 5$ and $det (B) = 2$
We know that
$det (K \cdot A) = K^{n} det (A),$ where $n$ is the order of determinant and $K \in R$
Now, $det (det (B) \cdot A) = det (2 \cdot A)$
$= 2^{3} \cdot det (A)$
$= 8 det (A)$
$∴ det (det (B) \cdot A) = 40$

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Similar questions

Q. If A and B are square matrices of order 2, then det (A + B) = 0 is possible only when
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Q. Consider the following in respect of two non-singular matrices

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of same order:

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Q. Let A,B,C be three square matrices of order

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Let A and B be two square matrices of order 3 such that det(A)=5 and det(B)=2. Then the value of det(det(B)⋅A) is

The correct option is A 40Given : det(A)=5 and det(B)=2 We know that det(K⋅A)=Kndet(A), where n is the order of determinant and K∈R Now, det(det(B)⋅A)=det(2⋅A) =23⋅det(A) =8det(A) ∴det(det(B)⋅A)=40

Let $A$ and $B$ be two square matrices of order $3$ such that $det (A) = 5$ and $det (B) = 2.$ Then the value of $det (det (B) \cdot A)$ is

The correct option is A $40$
Given : $det (A) = 5$ and $det (B) = 2$
We know that
$det (K \cdot A) = K^{n} det (A),$ where $n$ is the order of determinant and $K \in R$
Now, $det (det (B) \cdot A) = det (2 \cdot A)$
$= 2^{3} \cdot det (A)$
$= 8 det (A)$
$∴ det (det (B) \cdot A) = 40$