Let a,b and c be distinct non-negative numbers. If the vectors ai+aj+ck,i+k and ci+cj+bk lie in a plane, then c is
A
The harmonic mean of a and b
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B
Equal to zero
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C
The arithmetic mean of a and b
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D
The geometric mean of a and b
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Solution
The correct option is D The geometric mean of a and b Let a=ai+aj+ck,b=i+k and c=ci+cj+bka,b and c lies in a plane, if [abc]=0 ⇒∣∣
∣∣aac101ccb∣∣
∣∣=0 Applying C1→C1−C2 ⇒∣∣
∣∣0ac1010cb∣∣
∣∣=0 ⇒1⋅[ab−c2]=0 ⇒ab=c2 Therefore, c is geometric mean of a and b.