CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let a, b, and c be positive integers(a<b<c). If the average (arithmetic mean) of a, b, and c is 100, which of the following is NOT a possible value of any of the integers?

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
100
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
297
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
298
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
299
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C 299
Formula for mean is m=a+b+c3.
Substituting the value in the formula for Mean, m=a+b+c3=100
a+b+c=300
a<b<c lies between 0 and 299.
where,
(a,b,c)0 and (a,b,c)298
In case E
if c=299 then b=1 and a=0. This is not possible since a,b,c are positive integers.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Terms in an Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon