Question

Let, $n$ be an integer greater than $1$. Let, $a=$ the average (arithmetic mean) of the integers from $1$ to $n$ and let, $b=$ the average of the integers from $0$ to $n$. Which of the following could be true?
1) $a=b$

2) $a<b$

3) $a>b$

• A. $1$
• B. $2$
• C. $3$
• D. None of these

Answer 1

Answer: (C)

$3$

$n>1(n\in I)$

$a$$=$ Average number of Integer from $1$ to $n$

$b$$=$The Average number of Integer from $0$ to $n$

Number of Integer from$1$ to $n$ is less than the number of Integers from $0$ to $n$

Average of $1$ to $n$$>$Average of $0$ to $n$

$a$$>$$b$