Let A be a matrix of order3×3 and matrices B, C, D are related such that B = adj(A), C = adj(adj A), D \(= adj (adj(adj(A)))\). If |adj(adj(adj(adj(ABCD))))| is Ak then k
A
Is less than 256
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B
Has 21 divisors
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C
Greater than 256
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D
Is an odd number
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Solution
The correct option is AIs less than 256 Let ABCD = E ∴|adj(adj(adj(adj(ABCD))))| =|adj(adj(adj(adj(E))))| =|E|(3−1)4=|E|16 =|ABCD|16=|A|16|B|16|C|16|D|16 =|A|16.(|A|3−1)16.(|A|(3−1)2)16.(|A|(3−1)3)16 =|A|16+32+64+128=AK ⇒K=240; which is less than 256.