Let A be a non-empty set such that A- A has 9 elements among which -2-0-0-2 are found- Then A is equal to

We have ( 2,0) and (0,2) ∈ A× A ⇒{ 2,0,2}→ A nbsp; Also, A× A has 9 elements nbsp; ∴ A={ 2,0,2} nbsp; ...

353

You visited us 353 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Cartesian Product

Let A be a no...

Question

Let $A$ be a non-empty set such that $A \times A$ has $9$ elements among which $(- 2, 0), (0, 2)$ are found. Then $A$ is equal to

{- 2, 0}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{0, 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{- 2, 0, 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{- 2, - 1, 0, 1, 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${- 2, 0, 2}$
We have $(- 2, 0)$ and $(0, 2) \in A \times A$
$\Rightarrow {- 2, 0, 2} \to A$
Also, $A \times A$ has $9$ elements

$∴ A = {- 2, 0, 2}$

Suggest Corrections

Similar questions

Q. Let

A

be a non-empty set such that

A \times A

has

9

elements among which

(- 2, 0), (0, 2)

are found. Then

A

is equal to

Q. Let

A

be a non-empty set such that

A \times A

has

9

elements among which are found

(- 1, 0)

and

(0, 1)

, then

Let A be a non-empty set such that A $\times$ A has 9 elements among which are found (-1,0) and (0,1), then

Q. Let

A

be a non-empty set such that

A \times A

has

16

elements among which three elements are found to be

(a, b), (b, c)

and

(c, d)

and

I_{A}

be the identity relation on

A,

then

Q. Let

A

be a non-empty set such that

A \times A

has

9

elements and

(- 1, 0), (0, 1)

are elements of

A \times A

, then

A =

Join BYJU'S Learning Program

Let A be a non-empty set such that A×A has 9 elements among which (−2,0),(0,2) are found. Then A is equal to

The correct option is C {−2,0,2}We have (−2,0) and (0,2)∈A×A ⇒{−2,0,2}→A Also, A×A has 9 elements ∴A={−2,0,2}

Let $A$ be a non-empty set such that $A \times A$ has $9$ elements among which $(- 2, 0), (0, 2)$ are found. Then $A$ is equal to

The correct option is C ${- 2, 0, 2}$
We have $(- 2, 0)$ and $(0, 2) \in A \times A$
$\Rightarrow {- 2, 0, 2} \to A$
Also, $A \times A$ has $9$ elements

$∴ A = {- 2, 0, 2}$