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Domain

Let A be se...

Question

Let $A$ be set of first ten natural numbers and $R$ be a relation on $A$ defined by (x , y) $\in$ $R$ $\Rightarrow$ x + 2y = 10 , then domain of $R$ is

{1, 2, 3, . . . . . . . . . . . ., 10}

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{2, 4, 6, 8}

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{1, 2, 3, 4}

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{2, 4, 6, 8, 10}

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Solution

The correct option is A ${2, 4, 6, 8}$
$\begin{matrix} A & = {1, 2, 3, \dots \dots, 10} R & = {(x, y) : x + 2 y = 10, x, y \in A} ∴ y = \frac{10 - x}{2} R & = {(2, 4), (4, 3), (6, 2), (8, 1)} ∴ & Domain of R is {2, 4, 6, 8} \end{matrix}$
Correct option is (B).

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