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Question

Let A=[1234] and B=[abcd] are two matrices such that AB = BA and c0, then value of ad3bc is :

A
2
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B
-2
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C
-1
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Solution

The correct option is C -1
AB=[1234][abcd]=[a+2cb+2d3a+4c3b+4d]BA=[abcd][1234]=[a+3b2a+4bc+3d2c+4d]

Given that AB = BA.
How do we use the fact that two matrices are equal. In such a case we can equate the values of corresponding elements of both matrices.
First let's equate the element present in row 1 and column 1 of both matrices.
a + 2c = a + 3b------------------(1)

2c=3bb0
(since it is given that c is non-zero)
Next we will equate the element present in row 1 and column 2 of both matrices
b + 2d = 2a + 4b
2a - 2d = -3b ------------------(2)
Now we will equate the element present in row 2 and column 1 of both matrices
3a + 4c = c + 3d

3a + 3c = 3d.-----------------------(3)
Solve the three equations (1),(2) and (3) to obtain values of a, c and d in terms of b. In the required expression, substitute the values thus obtained as below.
ad3bc=32b3b32b=1.

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