Question

Let a fully charged lead_storage battery contains 1.5L of 5M

H₂SO₄ . What will be the concentration of H₂SO₄ in the battery after 2.5 A current is drawn from the battery for 6 hours ?

Opts-

A. 0.1865M

B. 4.626M

C . 0.373M

D. 9.627M

Answer 1

2.50 A ) (6.00 hrs) (3600 s/hr) = 54000 C
number of moles of electrons = 54000 C / 96500 C/mole of e- = 0.559 mole
0.559 mole of electrons --> 0.559 moles of H2SO4 consumed

initial moles of sulfuric acid = 1.50 L x 5.00M = 7.50 moles
final moles of sulfuric acid = 7.50 - 0.559 = 6.941 moles
final concentration of sulfuric acid = 4.627 M(No of moles Divide by 1.5(normality) to get concentration)

Option B