f(x)=x2−x21+x2
⇒f(x)=x41+x2
Now, replace x by −x,
f(−x)=(−x)41+(−x)2=x41+x2
⇒f(−x)=f(x)
⇒f(x) is an even function, hence it is many one.
Since, f(x)≥0 ∀ x∈R, so f(x) does not take any negative value.
So, range of f(x) is not R.
Hence, it is not onto.
⇒f(x) is neither one-one nor onto.