Let A=oddnumber≤19. Insert the appropriate symbol '∈‘ or '∉' in the blanks.
2......A
Given A=oddnumber≤19
A=....-3,-1,1,3,5,7,9,11,13,15,17,19
It can be clearly seen 2 does not belong to A=....-3,-1,1,3,5,7,9,11,13,15,17,19
Hence, 2∉A
Let A = {1, 2, 3, 4, 5, 6}. Insert the appropriate symbol ∈or ∉ in the blank spaces:
(i) 5…A (ii) 8…A (iii) 0…A
(iv) 4…A (v) 2…A (vi) 10…A
2. If E=evenintegers, then insert the appropriate symbol ∈or∉in the blanks :
(iii) 13____E
(vi) -4,12____E