Let A - x- x - R- -x- - 2- B - x - x - R- -x - 2- - 2 and A - B - R - C- then the set C equals

The correct option is D None of these A = { x:xϵ R, | x | lt; 2 } = { x:xϵ R, 2 lt; x lt; 2 } B = { x:xϵ R; | x 2 | lt; 2 } = { x :xϵ R,0 ...

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Derivative

Let A = x: ...

Question

Let $A = {x : x \in R, | x | < 2}, B = {x : x \in R, | x - 2 | \geq 2}$ and $A \cap B = R - C$ , then the set $C$ equals

{x : - 2 < x \leq 2}

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{x : - 2 \leq x \leq 4}

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{x : 2 \leq x < 4}

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None of these

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Solution

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Similar questions

A = [x ∶ x \in R, | x | < 1];

B = [x ∶ x \in R, | x - 1 | \geq 1]

A \cup B = R - D

D

A = {x : - 1 < x < 1; x \in R}

B = {x : x \leq 0 or x \geq 2; x \in R}

A \cup B = R - C

C

A = {x; x \in R, x \geq 2}

B = {x : x \in R, x < 4}

A \cap B =

Let $U = R ($ the set of all real numbers $)$ If $A = {x : x \in R, 0 < x < 2}, B = {x : x \in R, 1 < x \leq 3}$ , then

A = {x : x \in R, | x | < 1}

B = {x : x \in R, | x - 1 | \geq 1}

A \cup B = R - D

D

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