Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and ∠B=90∘, BD is perpendicular B to AC. The circle through BCD is drawn. Construct the tangents from A to the circle.
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Solution
Step (1): Draw a ΔABC and perpendicular from B on AC. Step (2): Draw a circle with BC as a diametre. This circle will pass through D Step (3): Let O be the midpoint of BC. Join AO Step (4): Draw a circle with AO as a diametre. This circle cuts the circle drawn in Step(2) at B and E. Step (5): Join AE. AE and AB are desired tangents drawn A to the circle passing thorugh B, C and D.