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Question

Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and B=90, BD is perpendicular B to AC. The circle through BCD is drawn. Construct the tangents from A to the circle.

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Solution


Step (1): Draw a ΔABC and perpendicular from B on AC.
Step (2): Draw a circle with BC as a diametre. This circle will pass through D
Step (3): Let O be the midpoint of BC. Join AO
Step (4): Draw a circle with AO as a diametre. This circle cuts the circle drawn in Step(2) at B and E.
Step (5): Join AE.
AE and AB are desired tangents drawn A to the circle passing thorugh B, C and D.

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