Question

Let $ABC$ be right triangle in which $AB=6cm,BC=8cm$ and $\angle B={90}^o$, $BD$ is the perpendicular from $B$ on $AC$. The circle through $B,C,D$ is drawn. Construct the tangents from $A$ to this circle.

Answer 1

Construct the $△ABC$ and $BD\perp AC$ then draw a circle with centre O such that $BO=OC=4cm$

join the point $O$ and $A$ and locate $M$ be the midpoint of $AO$. and draw a circle with centre M and radius $=MO=AM$

let this circle cuts the previous circle at $P$ and $Q$

Now join $AP$ and $AQ$ which are the desire tangents.