Question

# Let $$ABC$$ be right triangle in which $$AB=6\ cm,\ BC=8\ cm$$ and $$\angle B={90}^{o}$$, $$BD$$ is the perpendicular from $$B$$ on $$AC$$. The circle through $$B,C,D$$ is drawn. Construct the tangents from $$A$$ to this circle.

Solution

## Construct the $$\triangle ABC$$ and $$BD \bot AC$$ then draw a circle with centre O such that $$BO = OC = 4cm$$join the point $$O$$ and $$A$$ and locate $$M$$ be the midpoint of $$AO$$. and draw a circle with centre M and radius $$= MO = AM$$let this circle cuts  the previous circle at $$P$$ and $$Q$$Now join $$AP$$ and $$AQ$$ which are the desire tangents.MathematicsRS AgarwalStandard X

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