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Question

Let $$ABC$$ be right triangle in which $$AB=6\ cm,\ BC=8\ cm$$ and $$\angle B={90}^{o}$$, $$BD$$ is the perpendicular from $$B$$ on $$AC$$. The circle through $$B,C,D$$ is drawn. Construct the tangents from $$A$$ to this circle.


Solution


Construct the $$\triangle ABC$$ and $$BD \bot AC$$ then draw a circle with centre O such that $$BO = OC = 4cm$$

join the point $$O$$ and $$A$$ and locate $$M$$ be the midpoint of $$AO$$. and draw a circle with centre M and radius $$= MO = AM$$

let this circle cuts  the previous circle at $$P$$ and $$Q$$

Now join $$AP$$ and $$AQ$$ which are the desire tangents.

752899_465220_ans_8f96e88b8f004dec88374113fcc67dad.png

Mathematics
RS Agarwal
Standard X

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