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Question

Let C0,C1,....Cn denotes the binolmial coefficients in the expansion of (1+x)n. The value of C12C2+3C34C4+..... (upto n terms) is

A
2n
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B
2n
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C
0
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D
1
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Solution

The correct option is C 0
Expansion of (1+x)n is =C0+C1x+C2x2+Cnxn
On differentiating both sides w.r.t x, we get
n(1+x)x1=C1+2C2x+3C3x2++nCnxn1
putting x=1
C12C2+3C3+(1)n1nCn=0

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