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Question

Let
Δ=∣ ∣ ∣sin235sin255tan(55+80)sin211tan(79+56)sin279cos218cos272cot(72+63)∣ ∣ ∣
then Δ equals

A
-1
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B
0
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C
2
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D
(5+1)/8
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Solution

The correct option is B 0
Δ=∣ ∣ ∣sin235sin255tan(55+80)sin211tan(79+56)sin279cos218cos272cot(72+63)∣ ∣ ∣

=∣ ∣ ∣sin235cos235tan135sin211tan135cos211cos218sin218cot135∣ ∣ ∣

=∣ ∣ ∣sin235cos2351sin2111cos211cos218sin2181∣ ∣ ∣

applying C1C1+C2+C3 gives

=∣ ∣ ∣0cos235101cos2110sin2181∣ ∣ ∣=0

Δ=0

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