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Question

Let Δ=∣ ∣sinθcosϕsinθsinϕcosθcosθcosϕcosθsinϕsinθsinθsinϕsinθcosϕ0∣ ∣, then

A
Δ is independent of θ
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B
Δ is independent of ϕ
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C
Δ is a constant
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D
Δ is dependent of ϕ
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Solution

The correct option is B Δ is independent of ϕ
=sinθcosϕsinθsinϕcosθcosθcosϕcosθsinϕsinθsinθsinϕsinθcosϕ 0

expanding through R3 we get

sinθsinϕ(sin2θsinϕcos2θsinϕ)sinθcosϕ(sin2θcosϕcos2θcosϕ)

=sinθsin2ϕ(sin2θ+cos2θ)+sinθcos2ϕ(sin2θ+cos2θ)

=sinθsin2ϕ+sinθcos2ϕ=sinθ(sin2ϕ+cosϕ)

=sinθ

Independent of ϕ


















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