Let pq-3- then p2-q2p2-q2 is equal to

Given : #160; pq=3 ⇒ p=3q from question #160; =p^2 q^2p^2+q^2 =(3q)^2 q^2(3q)^2+q^2 =9q^2 q^29q^2+q^2 =8q^210q^2 =0.8 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Order of Operations

Let pq=3, t...

Question

Let $\frac{p}{q}$ =3, then $\frac{p^{2} - q^{2}}{p^{2} + q^{2}}$ is equal to

Open in App

Solution

Suggest Corrections

Similar questions

p^{2} + q^{2} = 21

p q = 30

(p + q)^{2}

p^{2} - 2 p q + q^{2}

p^{2} + 2 p q - q^{2}

a_{1}, a_{2}, a_{3}, . . . .

\frac{a_{1} + a_{2} + . . . . . + a_{p}}{a_{1} + a_{2} + . . . . . + a_{q}} = \frac{p^{2}}{q^{2}}, p \neq q

\frac{a_{6}}{a_{21}}

p^{2} x^{2} + (p^{2} - q^{2}) x - q^{2} = 0, p \neq 0

p q x^{2} - (p^{2} + q^{2}) x + p q = 0,

x

Join BYJU'S Learning Program