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Question

Let f(x)=1tanx4xπ, xπ4 , then limxπ4f(x)=

A
1
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B
12
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C
12
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1
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Solution

The correct option is B 12
f(x)=1tanx4xπ
limxπ4f(x)=limxπ4(1tanx4xπ)
Applying LHospitals rule we get,
=limxπ4(sec2x4)=sec2π44=24
limxπ4f(x)=12

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