Let P(x)=a0+a1x2+a2s4+........+anx2n be a polynomial in a real variable x with 0<a0<a1<a2<....<an′ The function P(x) has
A
neither a maximum nor a minimum
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
only one maximum
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
only one minimum
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
only one maximum and only one minimum
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D only one minimum P(x)=a0+a1x2+a2s4+........+anx2n P′(x)=2a1x+4a2x3+..............+2nanx2n−1 ⇒P′(x)=x(2a1+4a2x2+..............+2nanx2n−2) For extrema of P(x) P′(x)=0⇒x(2a1+4a2x2+..............+2nanx2n−2)=0 ⇒x=0 is only solution of this equation Also P′′(0)>0 Hence x=0 is only minima of P(x)