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Byju's Answer
Standard XII
Mathematics
Graphs of Basic Inverse Trigonometric Functions
Let f: [0, ...
Question
Let
f
:
[
0
,
4
π
]
→
[
0
,
π
]
be defined by
f
(
x
)
=
c
o
s
−
1
(
c
o
s
x
)
. The number of points
x
∈
[
0
,
4
π
]
satisfying the equation
f
(
x
)
=
10
−
x
10
is ................
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Solution
f
:
[
0
,
4
π
]
→
[
0
,
π
]
,
f
(
x
)
=
c
o
s
−
1
(
c
o
s
x
)
⇒
point A, B, C satisfy
f
(
x
)
=
10
−
x
10
Hence, 3 points
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2
Similar questions
Q.
If
f
:
[
0
,
4
π
]
→
[
0
,
π
]
be defined by
f
(
x
)
=
c
o
s
−
1
(
c
o
s
x
)
Then, the number of points
x
ϵ
[
0
,
4
π
]
satisfying the equation
f
(
x
)
=
10
−
x
10
, is
___
Q.
Let
f
:
[
0
,
4
π
]
→
[
0
,
π
]
be defined by
f
(
x
)
=
cos
−
1
(
cos
x
)
. The number of points
x
∈
[
0
,
4
π
]
satisfying the equation
f
(
x
)
=
10
−
x
10
is
Q.
Number of points, where
f
(
x
)
=
cos
|
x
|
+
|
sin
x
|
is not differentiable in
x
∈
[
0
,
4
π
]
, is:
Q.
Number of points where
f
(
x
)
=
cos
|
x
|
+
|
sin
x
|
is not differentiable in
x
∈
(
0
,
4
π
)
, is:
Q.
Let
g
(
x
)
be a polynomial of degree one and
f
(
x
)
be defined by
f
(
x
)
=
{
g
(
x
)
,
x
≤
0
|
x
|
s
i
n
x
,
x
>
0
If
f
(
x
)
is continuous satisfying
f
′
(
1
)
=
f
(
−
1
)
, then
g
(
x
)
is
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Standard XII Mathematics
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