Let f be a function satisfying the functional equation f(x)+2f(2x+1x−2)=3x,x≠2; then, the value of f(7) is
A
5
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B
-5
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C
1
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D
-1
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Solution
The correct option is D -1 Replace x→2x+1x−2 f(2x+1x−2)+2f(x)=3(2x+1x−2)−(1)
Given f(x)+2f(2x+1x−2)=3x−(2)
Solving (1) & (2) f(x)=−x2+6x+2x−2 f(7)=44−495=−1