wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let f be a polynomial function such that for all real x,f(x2+1)=x4+5x2+2 , then f(x)dx is

A
x33+3x222x+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x33+3x22+2x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x333x222x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x333x22+2x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x33+3x222x+c
f(x2+1)=x4+5x2+2

f(x2+1)=x4+2x2+1+3x2+31

f(x2+1)=(x2+1)2+3(x2+1)2

f(x)=x2+3x2

Let I=f(x)dx

=(x2+3x2)dx

I=x33+3x332x+c


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Higher Order Derivatives
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon