Let f - - be a function such that fm-n - fm - fn for every m- n - If f6 - 18- then f2- f3 is equal to

∵ f(m+n) = f(m) + f(n), nbsp;f : ℕ→ℕ ∴ f(x) = kx ∵ nbsp;f(6) = 18 ⇒ 18 = k·6 ⇒ k = 3 ∴ f(x) = 3x ∴ f(2)· f(3) = 6 × 9= 54 ...

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Cube Root of a Complex Number

Let f : ℕ→ℕ b...

Question

Let $f : N \to N$ be a function such that $f (m + n) = f (m) + f (n)$ for every $m, n \in N .$ If $f (6) = 18,$ then $f (2) \cdot f (3)$ is equal to

18

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6

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54

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36

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Similar questions

f : N \to N

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