CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Let f:RR be a function defined by f(x)=x3+x2+3x+sinx. Then f is

A
injective and surjective
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
injective but not surjective
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
surjective but not injective
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
neither injective nor surjective
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A injective and surjective
f(x)=x3+x2+3x+sinx, xR
f(x)=3x2+2x+3+cosx
f(x)=g(x)+cosx
g(x)>0 as D=436=32<0
Range of g is [D4a,)
i.e., range of g is [+3212,)=[83,)
Also, 1cosx1
f(x)>0
Hence, function f is strictly increasing.
f is injective.

limxf(x)=
and limxf(x)=
Also, f is continuous over R.
Range of f is R
f is surjective.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Types of Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon