f(x) = 10x + 7. Find the function g:R→R such that gof=fog=IR
Solve to calculate g:R→R.
Given: f:R→R be defined as f(x) = 10x + 7
Let g is the inverse of f
Again, let f(x)=y
y=10x+7
y−7=10x
10x=y−7
x=y−710
Let g(y)=y−710
where g:R→R
gof=g(f(x))=g(10x+7)
= (10x+7)−710
= 10x+7−710
= 10x10=x
gof=IR
fog=f(g(y))
=f(y−710)
=10(y−710)+7=y−7+7
=y+0=y
=IR
Since, gof=fog=IR
So, g(x)=x−710.