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Question

Let f:R(35}R(35} be defined by  f(x)=3x+25x3.
Then 
  1. f1(x)=f(x)
  2. f1(x)=f(x)
  3. fof(x)=x
  4. f1(x)=119f(x)


Solution

The correct option is A f1(x)=f(x)
Let y = f(x)y=3x+25x35xy3y=3x+25xy3x=3y+2x(5y3)=3y+2x=3y+25y3f1(y)=3y+25y3   [ y=f(x)x=f1(y)]f1(x)=3x+25x3=f(x)

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