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Question

Let f : R → R be defined by fx=1x. Then, f is
(a) one-one
(b) onto
(e) bijective
(d) not defined

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Solution

Given: The function f : R → R be defined by fx=1x.

To check f is one-one:

Let fx1=fx21x1=1x2x1=x2Hence, f is one-one.To check f is onto: Since, y=1xx=1yyR-0RThere is no pre-image of y=0.Hence, f is not onto.

Hence, the correct option is (a).


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