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Question

Let f:RR defined by f(x)=x21+x2
f is

A
injective
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B
surjective
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C
bijective
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D
neither injective nor surjective
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Solution

The correct option is C neither injective nor surjective
f(x)=x21+x2=111+x2
Clearly domain of f(x) is R and range is [0,1)
also f(1)=f(1). Hence this function is neither injective not surjective.

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