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Question

Let f(x) be a polynomial such that f(12)

=0, then a factor of f(x) is


A

x - 2

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B

x + 2

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C

2x - 1

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D

2x + 1

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Solution

The correct option is D

2x + 1


f(12)=0

x=12 2x =-1

2x + 1 = 0

2x + 1 is a factor of f(x)


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