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Question

Let f(x) = {x3+x216x+20(x2)2, if x2k, if x=2. if f(x) be continuous for all x, then k =

A
7
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B
-7
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C
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D
None of these
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Solution

The correct option is A 7

For continuous limx2f(x)=f(2)=k
k=limx2x3+x216x+20(x2)2
=limx2(x24x+4)(x+5)(x2)2=7.


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