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Question

Let f(x)=1ax+b then f′′(0)=

A
2a3b2
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B
2a2b3
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C
2a3b3
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D
none of these
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Solution

The correct option is A 2a2b3
Given,
f(x)=1ax+b
Now differentiating both sides with respect to x we get,
f(x)=a(ax+b)2
Again differentiating both sides with respect to x we get,
f′′(x)=2a2(ax+b)3
So f′′(0)=2a2b3.

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