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Question

Let f(x)=sin4x+cos4x. Then f is an increasing function in the interval:

A
[5π8,3π4]
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B
[π2,5π8]
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C
[π4,π2]
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D
[0,π4]
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Solution

The correct option is B [π4,π2]
f(x)=sin4x+cos4x

f(x)=4sin3xcosx+4cos3x(sinx)
=4sinxcosx(sin2xcos2x)
=2sin2xcos2x
=sin4x
f(x) is increasing when f(x)>0
sin4x>0
sin4x<0

4x(π,2π)
x(π4,π2)

509725_474835_ans.jpg

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