Let f(x)=sinx+cosx+tanx+arcsinx+arccosx+arctanx. If M and m are maximum and minimum values of f(x) then their arithmetic mean is equal to
A
π2+cos1
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B
π2+sin1
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C
π4+tan1+cos1
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D
π4+tan1+sin1
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Solution
The correct option is Aπ2+cos1 The domain of f(x) will be [−1,1] Hence f(−1) =−sin1+cos1−tan1−π2+π−π4 =m ...(i) f(1) =sin1+cos1+tan1+π2+0+π4 =M ...(ii) Hence M+m =2cos1+π Thus mean will be m+M2=cos1+π2