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Question

Let f(x)=x3+ax2+bx+5sin2x be an increasing function on the set R. Then, a and b satisfy

A
a23b15>0
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B
a23b+15>0
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C
a23b+15<0
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D
a>0 andb>0
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Solution

The correct option is C a23b+15<0
f(x)=x3+ax2+bx+5sin2x x[0,π2]

Given: Functionf(x) is increasing on the set R
Therefore,
f(x)>0

3x2+2ax+b5sin2x>0

Since,
f(x)>0;D<0 , Here D is discriminant

(2a)2(4×3)×(b5sin2x)<0

4a212b+60sin2x<0

a23b+15sin2x<0
Since, x[0,π2]
Therefore, sin2x>0
sin2x is always positive

Hence,
a23b+15<0

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