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Question

Let f(x)=x3+ax2+bx+5sin2x be an increasing function on the set R. Then, a and b satisfy.

A
a23b15>0
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B
a23b+15>0
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C
a23b+15<0
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D
a>0 and b>0
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Solution

The correct option is C a23b+15<0
f(x)=x3+ax2+bx+5sin2x
f(x)=3x2+2ax+b+5sin2x
Since f(x) is increasing.
Therefore,
f(x)>0
3x2+2ax+b+5sin2x>0
Minimum value of sin2x=1
Therefore,
3x2+2ax+b5>0
Since the above quadratic equation is >0, therefore, discriminant should be <0.
Therefore,
(2a)24(3)(b5)<0
4a212b+60<0
a23b+15<0
Hence for f(x) to be increasing function, a and b satisfy the equation a23b+15<0.

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