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Question

Let f(x+y)=f(x)f(y) and f(x)=1+xg(x)G(x), where
limx0g(x)=a and limx0G(x)=b. Then f(x) is equal to

A
1+ab
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B
ab
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C
f(x)
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D
abf(x)
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Solution

The correct option is D abf(x)
f(x)=Limh0f(x+h)f(x)h
=Limh0 f(x)(f(h)1h)
f(x)=f(x)f(0)
=f(x)f(0)
f(x)=g(x)G(x)+xg(x)G(x)+xg(x)G(x)
f(0)=ab+0+0
f(x)=(ab)f(x)
Hence,option 'D' is correct.

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