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Question

Let g(x)=1+x[x] and f(x)=1x<00,x=01,x>0 then for all x, f[g(x)] is equal to:

A
x
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B
1
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C
f(x)
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D
g(x)
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Solution

The correct option is B 1
g(x)=1+x[x] is greater than 1 since
x[x]>0
f{g(x)}=1 since f(x)=1 for all
x>0
Therefore, (b) is the answer.

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