Question

Let $g\left(x\right)$ be a function define on $(-1,1)$ so that the area of the equilateral triangle with two of its vertices at $(0,0)$ and$(x,g(x\left)\right)$ is $\frac{\sqrt{3}}{4}$. The function $g\left(x\right)$ is equal of

• A. $\sqrt{1-x^2}$
• B. $-\sqrt{1+x^2}$
• C. $\frac{1}{2}\sqrt{1-x^2}$
• D. $\frac{\sqrt{3}}{8}\sqrt{1-x^2}$

Answer 1

Answer: (A), (B)

The correct options are
A $\sqrt{1-x^2}$
B $-\sqrt{1+x^2}$