Question

Let $m$ be the class-mark and $u$ be the upper limit of a class in a continuous frequency distribution. The lower limit of the class is _________.

• A. $2m-u$
• B. $2m+u$
• C. $m-u$
• D. $m+u$

Answer 1

The correct option is A $2m-u$

Given:
Class-mark = $m$
Upper limit = $u$

We know that,
Class-mark = $\frac{Upperlimit+Lowerlimit}{2}$
$\therefore$ Lower limit = $2m-u$