1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Let 'M' be the mass and 'L' be the length of a thin uniform rod. In first case, axis of rotation is passing through centre and perpendicular to the length of the rod. In second case axis of rotation is passing through one end and perpendicular to the length of the rod. The ratio of radius of gyration in first case to second case is

A
1
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
14
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
18
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is A 12Moment of inertia of the rod about an axis passing through its centre and perpendicular to the length I1=112ML2Using Mk21=I1=112ML2We get radius of gyration k1=L√12Moment of inertia of the rod about an axis passing through its one end and perpendicular to the length I2=13ML2Using Mk22=I2=13ML2We get radius of gyration k2=L√3Thus ratio of radius of gyration k1k2=L/√12L/√3⟹ k1k2=12

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Moment of Inertia of Solid Bodies
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program