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Question

# Let nr and nb be respectively the number of photons emitted by a red bulb and a blue bulb of equal power in one second.

A

nr=nb

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B

nr<nb

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C

nr>nb

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D

The information is insufficient to get a relation between nr and nr.

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Solution

## The correct option is C nr>nb Let νr and vb be the freqencies of red and blue light respectively. We know that vb>vr. Also, nr red photons and nb blue photons are emitted each second. Now, since the two sources emit with equal power, the energy emitted per second will be - nr(hvr)=nb(hvb), which would imply, nrvr=nbvb. Since vb>vr, we can directly conclude: nr>nb! Option (c) is correct.

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