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Question

Let n(U)=700, n(A)=200, n(B)=300 and n(AB)=100,then n(AcBc) is -

A
400
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B
600
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C
300
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D
200
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Solution

The correct option is C 300
n(AcBc)=n((AB)c)
=n()n(AB)
=n()[n(A)+n(B)n(AB)]
= 700200300+100
= 300

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