Let nU -700- n A -200- n B -300 and n A - B -100-Then n A c - B c -A- 600B- 300C- 400D- 200

The correct option is B 300 n(A^c ∩ B^c) = n(∪) n(A ∪ B) = n(∪) [n(A) + n(B) n(A ∩ B)] = 700 [200 + 300 100] = 300. ...

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Cardinality of Sets

Let nU =700, ...

Question

Let n(U) = 700, n(A) = 200, n(B) = 300 and $n (A \cap B) = 100$ ,

Then $n (A^{c} \cap B^{c}) =$

400

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600

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300

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200

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Similar questions

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c}) =

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c}) =

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100

n (A^{C} \cap B^{C}) =

Let n(U) = 700, n(A) = 200, n(B) = 300 and $n (A \cap B) = 100$ ,

Then $n (A^{c} \cap B^{c}) =$

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c})

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