Let nU - 700- nA - 200- nB - 300 and nA - B - 100- then nAc - Bc equals to

From the given information n(U)=700, n(A)=200, n(B)=300 n(A∩ B)=100 Using nbsp; n(A^c∩ B^c) =n(A∪ B)^c nbsp; =n(U) n(A∪ B) =700 n(A) n(B)+n(A∩ B) =700 ...

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Standard XIII

Mathematics

De Morgan's Laws

Let nU = 700,...

Question

Let $n (U) = 700, n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100$ , then $n (A^{c} \cap B^{c})$ equals to

400

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600

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300

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20

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Solution

The correct option is C $300$
From the given information $n (U) = 700, n (A) = 200, n (B) = 300 n (A \cap B) = 100$

Using $n (A^{c} \cap B^{c}) = n (A \cup B)^{c} = n (U) - n (A \cup B) = 700 - n (A) - n (B) + n (A \cap B) = 700 - 200 - 300 + 100 = 300$

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Similar questions

Q. Let

n (U) = 700, n (A) = 200, n (B) = 300

and

n (A \cap B) = 100

. Then,

n (A^{c} \cap B^{c}) =

Q. Let

n (U) = 700, n (A) = 200, n (B) = 300

and

n (A \cap B) = 100

, then

n (A^{c} \cap B^{c}) =

Q. Let

n (U) = 700, n (A) = 200, n (B) = 300

and

n (A \cap B) = 100

, then

n (A^{c} \cap B^{c})

equals to

Let n(U) = 700, n(A) = 200, n(B) = 300 and n(A ∩ B) = 100,

Then n $(A^{c} \cap B^{c})$ =

Q. Let

n (U) = 700

n (A) = 200

n (B) = 300

and

n (A \cap B) = 100, then n (A^{c} \cap B^{c})

is -

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Let n(U)=700,n(A)=200,n(B)=300 and n(A∩B)=100, then n(Ac∩Bc) equals to

The correct option is C 300From the given information n(U)=700,n(A)=200,n(B)=300n(A∩B)=100 Using n(Ac∩Bc)=n(A∪B)c=n(U)−n(A∪B)=700−n(A)−n(B)+n(A∩B)=700−200−300+100=300

Let $n (U) = 700, n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100$ , then $n (A^{c} \cap B^{c})$ equals to

The correct option is C $300$
From the given information $n (U) = 700, n (A) = 200, n (B) = 300 n (A \cap B) = 100$

Using $n (A^{c} \cap B^{c}) = n (A \cup B)^{c} = n (U) - n (A \cup B) = 700 - n (A) - n (B) + n (A \cap B) = 700 - 200 - 300 + 100 = 300$