Let n U -700- n A -200- n B -300 and n A - B -100Then n A C - B c -A- 400B- 600C- 300D- 200

The correct option is C 300 n(A^c ∩ B^c) = n(∪) n(A ∪ B) = n(∪) [n(A) + n(B) n(A ∩ B)] = 700 [200 + 300 100] = 300. ...

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Quadratic Formula

Let n U =700,...

Question

Let n(U) = 700, n(A) = 200, n(B) = 300 and $n (A \cap B) = 100$ ,

Then $n (A^{c} \cap B^{c}) =$

400

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600

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300

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200

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Solution

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Let n(U) = 700, n(A) = 200, n(B) = 300 and n(A ∩ B) = 100,

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Let n (U) = 700, n (A) = 200, n (B) = 300, n (A \cap B) = 100, then n (A' \cap B') =

n (U) = 700, n (A) = 200, n (B) = 300

n (A \cap B) = 100

n (A^{c} \cap B^{c})

n (U) = 700

n (A) = 200

n (B) = 300

n (A \cap B) = 100, then n (A^{c} \cap B^{c})

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