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Question

Let n(U) = 700, n(A) = 200, n(B) = 300 and n(AB)=100,

Then n(AcBc)=


A

400

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B

600

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C

300

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D

200

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Solution

The correct option is C

300


n(AcBc)=n()n(AB)

=n()[n(A)+n(B)n(AB)]

=700[200+300100]=300.


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