If n-U- - 700- n-A- - 200- n-B- - 300 and n-A - B- - 100- then n -A- nbsp- nbsp-B- - - 400-300-200-600-

The correct option is B 300 By de Morgan's law of complementation, n(A' nbsp;∩ B') = n((A∪ B)') But, by the definition of a complement of a set, n((A∪ B)')=n ...

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Standard VIII

Mathematics

If n(U) = 700...

Question

If $n (U) = 700, n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100,$ then $n (A^{'} \cap B^{'}) =$ ___.

400

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600

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300

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200

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Solution

The correct option is C
300

By de-Morgan's law of complementation,
$n (A^{'} \cap B^{'}) = n ((A \cup B)^{'})$
But, by the definition of a complement of a set,
$n ((A \cup B)^{'}) = n (U) - n (A \cup B) .$

$= n (U) - [n (A) + n (B) - n (A \cap B)]$

$= 700 - [200 + 300 - 100]$

$= 300$ .

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Standard VIII Mathematics

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If n(U)=700, n(A)=200, n(B)=300 and n(A∩B)=100, then n(A′∩B′)= ___.

The correct option is C 300 By de-Morgan's law of complementation, n(A′∩B′)=n((A∪B)′) But, by the definition of a complement of a set, n((A∪B)′)=n(U)−n(A∪B). =n(U)−[n(A)+n(B)−n(A∩B)] =700−[200+300−100] =300.

If $n (U) = 700, n (A) = 200, n (B) = 300$ and $n (A \cap B) = 100,$ then $n (A^{'} \cap B^{'}) =$ ___.

The correct option is C
300

By de-Morgan's law of complementation,
$n (A^{'} \cap B^{'}) = n ((A \cup B)^{'})$
But, by the definition of a complement of a set,
$n ((A \cup B)^{'}) = n (U) - n (A \cup B) .$

$= n (U) - [n (A) + n (B) - n (A \cap B)]$

$= 700 - [200 + 300 - 100]$

$= 300$ .