Let nu-700-nA-200-nB-300 n A- B -100-n A- B- -

The correct option is C 300 Ans. (c). n(A∩ B)=n(A∪ B) =n(u) n(A∪ B) =n(u) { n( A ) +n( B ) n( A∩ B ) #160; } =700 { 200+300 100 } = ...

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De Morgan's Law

Let nu=700,...

Question

Let $n (u) = 700, n (A) = 200, n (B) = 300$
$n (A \cap B) = 100, n (A^{'} \cap B^{'}) =$

400

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600

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300

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N o n e

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